Optimal. Leaf size=173 \[ \frac {d^2 \text {Li}_3\left (-e^{2 i (a+b x)}\right )}{2 b^3}-\frac {d^2 \sin ^2(a+b x)}{b^3}-\frac {i d (c+d x) \text {Li}_2\left (-e^{2 i (a+b x)}\right )}{b^2}+\frac {2 d (c+d x) \sin (a+b x) \cos (a+b x)}{b^2}+\frac {(c+d x)^2 \log \left (1+e^{2 i (a+b x)}\right )}{b}+\frac {2 (c+d x)^2 \sin ^2(a+b x)}{b}-\frac {2 c d x}{b}-\frac {d^2 x^2}{b}-\frac {i (c+d x)^3}{3 d} \]
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Rubi [A] time = 0.33, antiderivative size = 173, normalized size of antiderivative = 1.00, number of steps used = 14, number of rules used = 9, integrand size = 23, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.391, Rules used = {4431, 4404, 3310, 4407, 3719, 2190, 2531, 2282, 6589} \[ -\frac {i d (c+d x) \text {PolyLog}\left (2,-e^{2 i (a+b x)}\right )}{b^2}+\frac {d^2 \text {PolyLog}\left (3,-e^{2 i (a+b x)}\right )}{2 b^3}+\frac {2 d (c+d x) \sin (a+b x) \cos (a+b x)}{b^2}-\frac {d^2 \sin ^2(a+b x)}{b^3}+\frac {(c+d x)^2 \log \left (1+e^{2 i (a+b x)}\right )}{b}+\frac {2 (c+d x)^2 \sin ^2(a+b x)}{b}-\frac {2 c d x}{b}-\frac {d^2 x^2}{b}-\frac {i (c+d x)^3}{3 d} \]
Antiderivative was successfully verified.
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Rule 2190
Rule 2282
Rule 2531
Rule 3310
Rule 3719
Rule 4404
Rule 4407
Rule 4431
Rule 6589
Rubi steps
\begin {align*} \int (c+d x)^2 \sec (a+b x) \sin (3 a+3 b x) \, dx &=\int \left (3 (c+d x)^2 \cos (a+b x) \sin (a+b x)-(c+d x)^2 \sin ^2(a+b x) \tan (a+b x)\right ) \, dx\\ &=3 \int (c+d x)^2 \cos (a+b x) \sin (a+b x) \, dx-\int (c+d x)^2 \sin ^2(a+b x) \tan (a+b x) \, dx\\ &=\frac {3 (c+d x)^2 \sin ^2(a+b x)}{2 b}-\frac {(3 d) \int (c+d x) \sin ^2(a+b x) \, dx}{b}+\int (c+d x)^2 \cos (a+b x) \sin (a+b x) \, dx-\int (c+d x)^2 \tan (a+b x) \, dx\\ &=-\frac {i (c+d x)^3}{3 d}+\frac {3 d (c+d x) \cos (a+b x) \sin (a+b x)}{2 b^2}-\frac {3 d^2 \sin ^2(a+b x)}{4 b^3}+\frac {2 (c+d x)^2 \sin ^2(a+b x)}{b}+2 i \int \frac {e^{2 i (a+b x)} (c+d x)^2}{1+e^{2 i (a+b x)}} \, dx-\frac {d \int (c+d x) \sin ^2(a+b x) \, dx}{b}-\frac {(3 d) \int (c+d x) \, dx}{2 b}\\ &=-\frac {3 c d x}{2 b}-\frac {3 d^2 x^2}{4 b}-\frac {i (c+d x)^3}{3 d}+\frac {(c+d x)^2 \log \left (1+e^{2 i (a+b x)}\right )}{b}+\frac {2 d (c+d x) \cos (a+b x) \sin (a+b x)}{b^2}-\frac {d^2 \sin ^2(a+b x)}{b^3}+\frac {2 (c+d x)^2 \sin ^2(a+b x)}{b}-\frac {d \int (c+d x) \, dx}{2 b}-\frac {(2 d) \int (c+d x) \log \left (1+e^{2 i (a+b x)}\right ) \, dx}{b}\\ &=-\frac {2 c d x}{b}-\frac {d^2 x^2}{b}-\frac {i (c+d x)^3}{3 d}+\frac {(c+d x)^2 \log \left (1+e^{2 i (a+b x)}\right )}{b}-\frac {i d (c+d x) \text {Li}_2\left (-e^{2 i (a+b x)}\right )}{b^2}+\frac {2 d (c+d x) \cos (a+b x) \sin (a+b x)}{b^2}-\frac {d^2 \sin ^2(a+b x)}{b^3}+\frac {2 (c+d x)^2 \sin ^2(a+b x)}{b}+\frac {\left (i d^2\right ) \int \text {Li}_2\left (-e^{2 i (a+b x)}\right ) \, dx}{b^2}\\ &=-\frac {2 c d x}{b}-\frac {d^2 x^2}{b}-\frac {i (c+d x)^3}{3 d}+\frac {(c+d x)^2 \log \left (1+e^{2 i (a+b x)}\right )}{b}-\frac {i d (c+d x) \text {Li}_2\left (-e^{2 i (a+b x)}\right )}{b^2}+\frac {2 d (c+d x) \cos (a+b x) \sin (a+b x)}{b^2}-\frac {d^2 \sin ^2(a+b x)}{b^3}+\frac {2 (c+d x)^2 \sin ^2(a+b x)}{b}+\frac {d^2 \operatorname {Subst}\left (\int \frac {\text {Li}_2(-x)}{x} \, dx,x,e^{2 i (a+b x)}\right )}{2 b^3}\\ &=-\frac {2 c d x}{b}-\frac {d^2 x^2}{b}-\frac {i (c+d x)^3}{3 d}+\frac {(c+d x)^2 \log \left (1+e^{2 i (a+b x)}\right )}{b}-\frac {i d (c+d x) \text {Li}_2\left (-e^{2 i (a+b x)}\right )}{b^2}+\frac {d^2 \text {Li}_3\left (-e^{2 i (a+b x)}\right )}{2 b^3}+\frac {2 d (c+d x) \cos (a+b x) \sin (a+b x)}{b^2}-\frac {d^2 \sin ^2(a+b x)}{b^3}+\frac {2 (c+d x)^2 \sin ^2(a+b x)}{b}\\ \end {align*}
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Mathematica [B] time = 6.56, size = 516, normalized size = 2.98 \[ \frac {c d \csc (a) \sec (a) \left (b^2 x^2 e^{-i \tan ^{-1}(\cot (a))}-\frac {\cot (a) \left (i \text {Li}_2\left (e^{2 i \left (b x-\tan ^{-1}(\cot (a))\right )}\right )+i b x \left (-2 \tan ^{-1}(\cot (a))-\pi \right )-2 \left (b x-\tan ^{-1}(\cot (a))\right ) \log \left (1-e^{2 i \left (b x-\tan ^{-1}(\cot (a))\right )}\right )-2 \tan ^{-1}(\cot (a)) \log \left (\sin \left (b x-\tan ^{-1}(\cot (a))\right )\right )-\pi \log \left (1+e^{-2 i b x}\right )+\pi \log (\cos (b x))\right )}{\sqrt {\cot ^2(a)+1}}\right )}{b^2 \sqrt {\csc ^2(a) \left (\sin ^2(a)+\cos ^2(a)\right )}}-\frac {\cos (2 b x) \left (2 b^2 c^2 \cos (2 a)+4 b^2 c d x \cos (2 a)+2 b^2 d^2 x^2 \cos (2 a)-2 b c d \sin (2 a)-2 b d^2 x \sin (2 a)-d^2 \cos (2 a)\right )}{2 b^3}+\frac {\sin (2 b x) \left (2 b^2 c^2 \sin (2 a)+4 b^2 c d x \sin (2 a)+2 b^2 d^2 x^2 \sin (2 a)+2 b c d \cos (2 a)+2 b d^2 x \cos (2 a)-d^2 \sin (2 a)\right )}{2 b^3}+\frac {i e^{-i a} d^2 \sec (a) \left (2 b^2 x^2 \left (2 b x-3 i \left (1+e^{2 i a}\right ) \log \left (1+e^{-2 i (a+b x)}\right )\right )+6 \left (1+e^{2 i a}\right ) b x \text {Li}_2\left (-e^{-2 i (a+b x)}\right )-3 i \left (1+e^{2 i a}\right ) \text {Li}_3\left (-e^{-2 i (a+b x)}\right )\right )}{12 b^3}+\frac {c^2 \sec (a) (b x \sin (a)+\cos (a) \log (\cos (a) \cos (b x)-\sin (a) \sin (b x)))}{b \left (\sin ^2(a)+\cos ^2(a)\right )}-\frac {1}{3} x \tan (a) \left (3 c^2+3 c d x+d^2 x^2\right ) \]
Warning: Unable to verify antiderivative.
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fricas [C] time = 0.55, size = 677, normalized size = 3.91 \[ \frac {2 \, b^{2} d^{2} x^{2} + 4 \, b^{2} c d x - 2 \, {\left (2 \, b^{2} d^{2} x^{2} + 4 \, b^{2} c d x + 2 \, b^{2} c^{2} - d^{2}\right )} \cos \left (b x + a\right )^{2} + 2 \, d^{2} {\rm polylog}\left (3, i \, \cos \left (b x + a\right ) + \sin \left (b x + a\right )\right ) + 2 \, d^{2} {\rm polylog}\left (3, i \, \cos \left (b x + a\right ) - \sin \left (b x + a\right )\right ) + 2 \, d^{2} {\rm polylog}\left (3, -i \, \cos \left (b x + a\right ) + \sin \left (b x + a\right )\right ) + 2 \, d^{2} {\rm polylog}\left (3, -i \, \cos \left (b x + a\right ) - \sin \left (b x + a\right )\right ) + 4 \, {\left (b d^{2} x + b c d\right )} \cos \left (b x + a\right ) \sin \left (b x + a\right ) + {\left (2 i \, b d^{2} x + 2 i \, b c d\right )} {\rm Li}_2\left (i \, \cos \left (b x + a\right ) + \sin \left (b x + a\right )\right ) + {\left (-2 i \, b d^{2} x - 2 i \, b c d\right )} {\rm Li}_2\left (i \, \cos \left (b x + a\right ) - \sin \left (b x + a\right )\right ) + {\left (-2 i \, b d^{2} x - 2 i \, b c d\right )} {\rm Li}_2\left (-i \, \cos \left (b x + a\right ) + \sin \left (b x + a\right )\right ) + {\left (2 i \, b d^{2} x + 2 i \, b c d\right )} {\rm Li}_2\left (-i \, \cos \left (b x + a\right ) - \sin \left (b x + a\right )\right ) + {\left (b^{2} c^{2} - 2 \, a b c d + a^{2} d^{2}\right )} \log \left (\cos \left (b x + a\right ) + i \, \sin \left (b x + a\right ) + i\right ) + {\left (b^{2} c^{2} - 2 \, a b c d + a^{2} d^{2}\right )} \log \left (\cos \left (b x + a\right ) - i \, \sin \left (b x + a\right ) + i\right ) + {\left (b^{2} d^{2} x^{2} + 2 \, b^{2} c d x + 2 \, a b c d - a^{2} d^{2}\right )} \log \left (i \, \cos \left (b x + a\right ) + \sin \left (b x + a\right ) + 1\right ) + {\left (b^{2} d^{2} x^{2} + 2 \, b^{2} c d x + 2 \, a b c d - a^{2} d^{2}\right )} \log \left (i \, \cos \left (b x + a\right ) - \sin \left (b x + a\right ) + 1\right ) + {\left (b^{2} d^{2} x^{2} + 2 \, b^{2} c d x + 2 \, a b c d - a^{2} d^{2}\right )} \log \left (-i \, \cos \left (b x + a\right ) + \sin \left (b x + a\right ) + 1\right ) + {\left (b^{2} d^{2} x^{2} + 2 \, b^{2} c d x + 2 \, a b c d - a^{2} d^{2}\right )} \log \left (-i \, \cos \left (b x + a\right ) - \sin \left (b x + a\right ) + 1\right ) + {\left (b^{2} c^{2} - 2 \, a b c d + a^{2} d^{2}\right )} \log \left (-\cos \left (b x + a\right ) + i \, \sin \left (b x + a\right ) + i\right ) + {\left (b^{2} c^{2} - 2 \, a b c d + a^{2} d^{2}\right )} \log \left (-\cos \left (b x + a\right ) - i \, \sin \left (b x + a\right ) + i\right )}{2 \, b^{3}} \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int {\left (d x + c\right )}^{2} \sec \left (b x + a\right ) \sin \left (3 \, b x + 3 \, a\right )\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [B] time = 0.13, size = 377, normalized size = 2.18 \[ -\frac {i d^{2} x^{3}}{3}+\frac {2 i d^{2} a^{2} x}{b^{2}}+i c^{2} x -\frac {\left (2 d^{2} x^{2} b^{2}+4 b^{2} c d x +2 i b \,d^{2} x +2 b^{2} c^{2}+2 i b c d -d^{2}\right ) {\mathrm e}^{2 i \left (b x +a \right )}}{4 b^{3}}-\frac {\left (2 d^{2} x^{2} b^{2}+4 b^{2} c d x -2 i b \,d^{2} x +2 b^{2} c^{2}-2 i b c d -d^{2}\right ) {\mathrm e}^{-2 i \left (b x +a \right )}}{4 b^{3}}+\frac {c^{2} \ln \left (1+{\mathrm e}^{2 i \left (b x +a \right )}\right )}{b}-\frac {2 c^{2} \ln \left ({\mathrm e}^{i \left (b x +a \right )}\right )}{b}-\frac {2 d^{2} a^{2} \ln \left ({\mathrm e}^{i \left (b x +a \right )}\right )}{b^{3}}-\frac {i d^{2} \polylog \left (2, -{\mathrm e}^{2 i \left (b x +a \right )}\right ) x}{b^{2}}+\frac {4 i d^{2} a^{3}}{3 b^{3}}-i c d \,x^{2}+\frac {d^{2} \ln \left (1+{\mathrm e}^{2 i \left (b x +a \right )}\right ) x^{2}}{b}-\frac {i c d \polylog \left (2, -{\mathrm e}^{2 i \left (b x +a \right )}\right )}{b^{2}}+\frac {d^{2} \polylog \left (3, -{\mathrm e}^{2 i \left (b x +a \right )}\right )}{2 b^{3}}+\frac {4 c d a \ln \left ({\mathrm e}^{i \left (b x +a \right )}\right )}{b^{2}}+\frac {2 c d \ln \left (1+{\mathrm e}^{2 i \left (b x +a \right )}\right ) x}{b}-\frac {2 i c d \,a^{2}}{b^{2}}-\frac {4 i c d a x}{b} \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [A] time = 0.45, size = 301, normalized size = 1.74 \[ -\frac {c^{2} {\left (2 \, \cos \left (2 \, b x + 2 \, a\right ) - \log \left (\cos \left (2 \, b x\right )^{2} + 2 \, \cos \left (2 \, b x\right ) \cos \left (2 \, a\right ) + \cos \left (2 \, a\right )^{2} + \sin \left (2 \, b x\right )^{2} - 2 \, \sin \left (2 \, b x\right ) \sin \left (2 \, a\right ) + \sin \left (2 \, a\right )^{2}\right )\right )}}{2 \, b} + \frac {-2 i \, b^{3} d^{2} x^{3} - 6 i \, b^{3} c d x^{2} + 3 \, d^{2} {\rm Li}_{3}(-e^{\left (2 i \, b x + 2 i \, a\right )}) + {\left (6 i \, b^{2} d^{2} x^{2} + 12 i \, b^{2} c d x\right )} \arctan \left (\sin \left (2 \, b x + 2 \, a\right ), \cos \left (2 \, b x + 2 \, a\right ) + 1\right ) - 3 \, {\left (2 \, b^{2} d^{2} x^{2} + 4 \, b^{2} c d x - d^{2}\right )} \cos \left (2 \, b x + 2 \, a\right ) + {\left (-6 i \, b d^{2} x - 6 i \, b c d\right )} {\rm Li}_2\left (-e^{\left (2 i \, b x + 2 i \, a\right )}\right ) + 3 \, {\left (b^{2} d^{2} x^{2} + 2 \, b^{2} c d x\right )} \log \left (\cos \left (2 \, b x + 2 \, a\right )^{2} + \sin \left (2 \, b x + 2 \, a\right )^{2} + 2 \, \cos \left (2 \, b x + 2 \, a\right ) + 1\right ) + 6 \, {\left (b d^{2} x + b c d\right )} \sin \left (2 \, b x + 2 \, a\right )}{6 \, b^{3}} \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [F] time = 0.00, size = -1, normalized size = -0.01 \[ \int \frac {\sin \left (3\,a+3\,b\,x\right )\,{\left (c+d\,x\right )}^2}{\cos \left (a+b\,x\right )} \,d x \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [F(-1)] time = 0.00, size = 0, normalized size = 0.00 \[ \text {Timed out} \]
Verification of antiderivative is not currently implemented for this CAS.
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